9n^2+21n-120=

Solution for 9n^2+21n-120= equation:

9n^2+21n-120=

We move all terms to the left:

9n^2+21n-120-()=0

We add all the numbers together, and all the variables

9n^2+21n=0

a = 9; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·9·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*9}=\frac{-42}{18}
=-2+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*9}=\frac{0}{18}
=0
$